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Episode 7 Supports
Episode Description
Reflecting: Sasha and Keoni discuss what the equation means. They also use it to find the equation of a parabola with a vertex on the origin and p = 0.5.
Students’ Conceptual Challenges
Students may have difficulty understanding the role that the parameter, p, plays in the equation y = x2/(4p). It may be confusing that the equation represents a family of parabolas.
Focus Questions
For use in a classroom, pause the video and ask these questions:
1. [Pause video at 0:59]. List everything you know about the parabola with a vertex at the origin and a focus 1/2 unit above the origin.
2. [Pause video at 6:35]. List everything you know about the equation y=x2/(4p).
Supporting Dialogue
Invite students to engage in a pair-share activity as they respond to each focus question:
Math Extensions
Consider the circle below.
1. Consider the two parabolas graphed below. Use the equations for each graph and geometric reasoning to label the coordinates of 4 points on each graph.
2. Compare the points and coordinates across the two parabolas. List any patterns that you notice.
Mathematics in this Lesson
Lesson Description
Targeted Understanding
CC Math Standards
CC Math Practices
Lesson Description
Keoni and Sasha determine a general method for representing the equation for a parabola with a vertex on the origin and a focus p units above the vertex.
Targeted Understandings
This lesson can help students:
Common Core Math Standards
• CCSS.M.HSG.GPE.A.2: Derive the equation of a parabola given a focus and directrix.
In Episode 6, Sasha and Keoni derive the equation (in two forms) for the family of parabolas with vertex (0,0) and focus p units above the vertex, namely y = x2/(4p) and x = √(4py). They do this by generalizing the method they used to develop an equation for a parabola with p = 1 in Lessons 3 and 4 (y = x2/4 and x = √(4y)), for a parabola with p = 2 in Episode 2 of this lesson (y = x2/8 and x = √(8y)), and for a parabola with p = 3 in Episode 4 (y = x2/12 and x = √(12y)).
• CCSS.M.HSA.APR.A.1: Perform arithmetic operations on polynomials.
Sasha and Keoni multiply binomials, such as (y + 2)2 and (y + p)2, in service of deriving an equation for a particular parabola (in Episodes 2 and 4) or a family of parabolas (Episode 6).
Common Core Math Practices
CCSS.Math.Practice.MP7. Look for and make use of structure.
In this lesson, Sasha and Keoni make use of mathematical structure on two levels. First, they discern a pattern relating the equations of three parabolas (y = x2/4, y = x2/8, and y = x2/12) with the corresponding distance between the vertex and focus (respectively, p = 1; p = 2; and p = 3). Specifically, they see the structure of 1•4, 2•4 and 3•4 in the denominators of their equations, which is the p-value of the parabola multiplied by 4. Consequently Keoni and Sasha conjecture that the general equation of a parabola with vertex (0,0) and focus p units above the vertex will be y = x2/(4p). Then they look for and make use of structure on a second level. To derive the equation y = x2/(4p), they need to identify the lengths of the sides of a right triangle with hypotenuse connecting a general point on the parabola with the focus. To accomplish this challenging task, Sasha and Keoni see a pattern in similar quantities that they identified for particular parabolas, which they generalize to define lengths involving the parameter p, such as y – p and y + p.