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Episode 2 Supports

  • Episode Description

    Exploring: Keoni and Sasha use the definition of a parabola and the Pythagorean theorem to solve for the y-value of a point on the parabola when the x-value is 5.

  • Students’ Conceptual Challenges

    Sasha and Keoni are unsure how to represent distances involving the unknown value of y [see 0:46 – 1:14].

     

    • Keoni returns with more confidence to his idea from Episode 1 of representing one of the distances as y – 1 [1:15]. 

  • Focus Questions

    For use in a classroom, pause the video and ask these questions:

     

    1. [Pause video at 1:54]. Keoni has written down an equation. Why is that equation true?

     

    2. [Pause video at 2:28]. Examine the expressions on both sides of the equals sign. How are they the same? How are they different?

  • Supporting Dialogue

    Facilitate the action of providing justification by asking students to:

     

    • Explain why the distance from the point (5, y) to the directrix is y + 1.  Support your argument by labeling y, 1, and y + 1 on the graph.

    • Explain why the length of the vertical side of the right triangle is y – 1. Support your argument by labeling y, 1, and y – 1 on the graph.

  • Math Extensions

    1.1. Multiply the binomials and simplify by combining like terms. What pattern do you see emerging?

     

    (4 + x)(x + 4)

    (x2 + x)(x2 + x)

    (x + y)(x + y)

    (5x – 2y)(5x – 2y)

    (4 – x)(4 – x)

     

    2. Justify by showing your work and explaining your reasoning. Are any of the following expressions are equivalent to 3xy?

     

    3x3y

    xy + xy + xy

    xy3

    x + x + x + y + y + y?

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Mathematics in this Lesson

Lesson Description

Targeted Understanding

CC Math Standards

CC Math Practices

Lesson Description

 

Sasha and Keoni use the definition of a parabola, the Pythagorean theorem, and their methods from previous lessons to represent the y-value for any point on a particular parabola, given the x-value of that point.  In contrast to Lesson 3 in which y-values were given, in this episode x-values will be given.

Targeted Understandings

 

This lesson can help students:

 

  • Interpret the algebraic expressions that are substituted into the Pythagorean theorem  (namely, y – 1, y + 1, and x), during the process of deriving an equation for a particular parabola, as distances on a coordinate grid.

  • Conceive of algebraic expressions, such as y – 1, as both a single entity and as a process of subtracting 1 from a number.

Common Core Math Standards

• CCSS.M.HSF.IF.C.8: Write a function defined by an expression in different but equivalent forms to reveal and explain different properties of the function.

Keoni and Sasha re-express the equation for a given parabola that they derived in Lesson 3 (namely, x = √(4y)) as y = x2/4. They discuss how the first form of the equation is easier to use when one is given a y-value and needs to determine the corresponding x-value, while the second form is easier to use when one is given an x-value. However, they recognize that the two forms are equivalent and that either can be used to solve both problems.

 

• CCSS.M.HSG.GPE.A.2. Define appropriate quantities for the purpose of descriptive modeling.

Sasha and Keoni use the geometric definition of a parabola, along with the Pythagorean theorem to derive the equation of a given parabola (namely, y = x2/4).

 

• CCSS.M.HSN.Q.A.2: Define appropriate quantities for the purpose of descriptive modeling.

As they work to derive the equation of a given parabola using the Pythagorean Theorem, Sasha and Keoni define three quantities that represent the lengths of the sides of a right triangle. Because they are using a general point (x,y) on the parabola (rather than a specific point), these distances are algebraic expressions: y–1, y+1, and x.

Common Core Math Practices

 

CCSS.Math.Practice.MP8. Look for and express regularity in repeated reasoning.

In this lesson, re-expressing the equation for a particular parabola, x = √(4y), as y = x2/4x, is not addressed simply as the application of algebraic manipulation skills. Rather, the process of re-expression illustrates the math practice of looking for and expressing regularity in repeated reasoning. In Episode 3, Sasha and Keoni use the equation x = √(4y) (which they derived in Lesson 3), to find the y-value for a point on the parabola when x = 5. They then repeat their reasoning for x = 10 and x = 437. By paying attention to the algebraic transformations they perform each time to isolate and solve for the y-value, they notice regularities which help them generalize their approach to solve x = √(4y)  for y in Episode 4. Approaching the act of re-expression as the generalization of repeated reasoning carries the benefit of reinforcing the equivalence of different forms of an equation and can help students deal with an abstract situation with more meaning.